In the following reaction 'X' is
CH$$_3$$(CH$$_2$$)$$_4$$CH$$_3$$ $$\xrightarrow{\text{Anhy. AlCl}_3 / \text{HCl}, \Delta}$$ X (major product)

A

B

C

CH$$_3$$(CH$$_2$$)$$_4$$CH$$_2$$Cl

D

Cl$$-$$CH$$_2-$$(CH$$_2$$)$$_4-$$CH$$_2-$$Cl