Be(OH)$$_2$$ reacts with Sr(OH)$$_2$$ to yield an ionic salt. Choose the incorrect option related to this reaction from the following

Be(OH)₂ is amphoteric. When it reacts with Sr(OH)₂ (a strong base), Be(OH)₂ acts as an acid:

$$\text{Be(OH)}_2 + \text{Sr(OH)}_2 \to \text{Sr[Be(OH)}_4]$$

or equivalently: $$\text{Be(OH)}_2 + 2\text{OH}^- \to [\text{Be(OH)}_4]^{2-}$$

The ionic salt formed is Sr[Be(OH)₄], where:

• Sr²⁺ is the cation
• [Be(OH)₄]²⁻ is the anion (beryllate ion)

Now let's check each option:

Option 1: Both Sr and Be are present in the ionic salt → Correct

Option 2: Be is tetrahedrally coordinated → Correct (4 OH groups around Be in [Be(OH)₄]²⁻)

Option 3: Be is present in the cationic part → Incorrect. Be is in the anionic part [Be(OH)₄]²⁻

Option 4: This is an acid-base neutralization reaction → Correct (amphoteric oxide acting as acid with a base)

The incorrect option is Option 3.