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$$Y = \overline{(A \cdot B) \cdot (B + \bar{A})}$$
Using the distributive law to simplify the expression inside the inversion bar:
$$= (A \cdot B \cdot B) + (A \cdot B \cdot \bar{A})$$
$$= (A \cdot B) + (0) = A \cdot B$$
$$Y = \overline{A \cdot B}$$
$$\overline{A \cdot B} = 0 \implies A \cdot B = 1$$
$$A = 1 \quad \text{and} \quad B = 1$$
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