Join WhatsApp Icon JEE WhatsApp Group
Question 35

Consider the following logic circuit. The output is Y = 0 when :

image

Solution

Share

$$Y = \overline{(A \cdot B) \cdot (B + \bar{A})}$$

Using the distributive law to simplify the expression inside the inversion bar:

$$= (A \cdot B \cdot B) + (A \cdot B \cdot \bar{A})$$

$$= (A \cdot B) + (0) = A \cdot B$$

$$Y = \overline{A \cdot B}$$

$$\overline{A \cdot B} = 0 \implies A \cdot B = 1$$

$$A = 1 \quad \text{and} \quad B = 1$$

Get AI Help

Create a FREE account and get:

  • Free JEE Mains Previous Papers PDF
  • Take JEE Mains paper tests
Ask AI