Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
To determine the correct IUPAC name of the given compound, we follow the standard IUPAC nomenclature rules for substituted aromatic compounds.
The molecule contains a benzene ring substituted with four functional groups:
Among these, the aldehyde group has the highest priority according to IUPAC nomenclature rules:
$$\text{Aldehyde} > \text{Alcohol} > \text{Amine} > \text{Nitro}.$$
Therefore, the aldehyde group is selected as the principal functional group, and the parent compound is benzaldehyde.
The carbon atom attached to the $$-CHO$$ group is assigned position $$1$$. The ring can then be numbered in either direction to obtain the lowest possible set of locants for the remaining substituents.
If numbered clockwise, the substituent positions are
$${3,,4,,6}.$$
If numbered counterclockwise, the substituent positions are
$${2,,4,,5}.$$
According to the lowest set of locants rule, the set
$${2,,4,,5}$$
is preferred because it gives the lower number at the first point of difference.
Thus, the substituent positions are:
The substituent prefixes are then arranged alphabetically:
Combining the substituents with their locants and the parent name gives the IUPAC name:
5-amino-4-hydroxymethyl-2-nitrobenzaldehyde.
Hence, the correct answer is
$$\boxed{\text{5-amino-4-hydroxymethyl-2-nitrobenzaldehyde}}.$$
Create a FREE account and get:
Educational materials for JEE preparation