From the top of an upright pole 17.75 m high, the angle of elevation of the top of an upright tower was $$60^{\circ}$$. If the tower was 57.75 m tall, how far away (in m) from the foot of the pole was the foot of the tower?

A

$$40\sqrt{3}$$

B

$$\frac{151\sqrt{3}}{6}$$

C

$$\frac{77}{4}\sqrt{3}$$

D

$$\frac{40\sqrt{3}}{3}$$