From the top of an upright pole $$24\sqrt{3}$$ feet high, the angle of elevation of the top of an upright tower was $$60^{\circ}$$. If the foot of the pole was 60 feet away from the foot of the tower, what tall (in feet) was the tower?

A

$$84\sqrt{3}$$

B

$$36\sqrt{3}$$

C

$$44\sqrt{3}$$

D

$$60\sqrt{3}$$