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Question 24

Let the image of the point $$P(0, -5, 0)$$ in the line $$\dfrac{x - 1}{2} = \dfrac{y}{1} = \dfrac{z + 1}{-2}$$ be the point R and the image of the point $$Q\left(0, \dfrac{-1}{2}, 0\right)$$ in the line $$\dfrac{x - 1}{-1} = \dfrac{y + 9}{4} = \dfrac{z + 1}{1}$$ be the point S. Then the square of the area of the parallelogram PQRS is __________.


Correct Answer: 162

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