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Let the line $$x - y = 4$$ intersect the circle $$C: (x - 4)^2 + (y + 3)^2 = 9$$ at the points Q and R. If $$P(\alpha, \beta)$$ is a point on C such that $$PQ = PR$$, then $$(6\alpha + 8\beta)^2$$ is equal to __________.
Correct Answer: 18
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