Sunlight of intensity 50 W m$$^{-2}$$ is incident normally on the surface of a solar panel. Some part of incident energy (25%) is reflected from the surface and the rest is absorbed. The force exerted on 1 m$$^2$$ surface area will be close to ($$c = 3 \times 10^8$$ m s$$^{-1}$$):

A

$$15 \times 10^{-8}$$ N

B

$$20 \times 10^{-8}$$ N

C

$$10 \times 10^{-8}$$ N

D

$$35 \times 10^{-8}$$ N