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A water tanker can be filled by 2 pipes A & B separately in 16 min & 32 min respectively. Outlet of
the tanker is partially open and it can empty the full tanker completely in 1 hour 4 min. Pipes A & B
were opened simultaneously for 9 min to fill the tanker but the partially open outlet was not closed.
After 9 min the pipes A & B were closed and the tanker then went to Mohan's house, 6 km away to
deliver water. If the tanker moved at a constant speed of 36 km/hr, approximately what percentage of
tanker was full, when it reached Mohan's house?
Let the tank capacity be 64 liters.
Hence, capacity of pipes A and B resp are 4 lit/min and 2 lit/min
Also, the capacity of the draining pipe = -1 lit/min
Now, when all pipes are open for 09 mins, tank filled = (4+2)*9 - (9*1) = 45 liters
Now, the tank travels for (6/36)*60 min = 10 minutes
During this time, liquid lost = 10*1 lit/min = 10 liters
Liquid left = 35 liters
hence, percentage filled = 35/64 = 55% approx
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