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If (a + b + c) = 6 and $$a^2 + b^2 + c^2$$ = 14, then (ab + bc + ca) = ?
22
11
33
44
$$(a + b + c)^2 =a^2 + b^2 + c^2 + 2(ab + bc + ca)$$
$$(6)^2 =14 + 2(ab + bc + ca)$$
36-14 = 2(ab + bc + ca)
(ab + bc + ca) = 11
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