In the circuit, the logical value of $$A = 1$$ or $$B = 1$$ when potential at $$A$$ or $$B$$ is $$5 \text{ V}$$ and the logical value of $$A = 0$$ or $$B = 0$$ when potential at $$A$$ or $$B$$ is $$0 \text{ V}$$.

The truth table of the given circuit will be:

$$\begin{array}{|c|c|c|}\hline A & B & Y \\ \hline 0 & 0 & 0 \\ 1 & 0 & 0 \\ 0 & 1 & 0 \\ 1 & 1 & 1 \\ \hline \end{array}$$

$$\begin{array}{|c|c|c|}\hline A & B & Y \\ \hline 0 & 0 & 0 \\ 1 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 1 & 1 \\ \hline \end{array}$$

$$\begin{array}{|c|c|c|}\hline A & B & Y \\ \hline 0 & 0 & 0 \\ 1 & 0 & 0 \\ 0 & 1 & 0 \\ 1 & 1 & 0 \\ \hline \end{array}$$

$$\begin{array}{|c|c|c|}\hline A & B & Y \\ \hline 0 & 0 & 1 \\ 1 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 1 & 0 \\ \hline \end{array}$$