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Question 20
A man walks 20 m towards north, then he turns right and walks 3 m, then turns left and walks 4 m and from there he walks 4 m towards east. How far and in which direction is he from his initial position?
Solution
Let the man starts from point A and walked 20 m north to reach point B, then he turned right towards east and walked for 3 m, from point C he turned left to reach D after walking 4 m and finally stopped at point E.
Thus, AE = $$\sqrt{(20+4)^2+(4+3)^2}$$
=> $$AE=\sqrt{576+49}=\sqrt{625}$$
=> $$AE=25$$ m
Thus, he is 25 m north-east of his original position.
=> Ans - (B)
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