If the normal stresses due to longitudinal and transverse loads on a bar are $$\sigma_1$$ and $$\sigma_2$$ respectively, the tangential component of the stress on an inclined plane through $$\theta^\circ$$, the longitudinal load is

A

$$ \sigma_1 \sin⁡ \theta + \sigma_2 \cos⁡ \theta $$

B

$$ \sigma_1 \sin^⁡{2} \theta + \sigma_2 \cos^2 ⁡\theta $$

C

$$\frac{(\sigma_1 - \sigma_2)(\sin⁡2 \theta )}{2}$$

D

$$ \frac{(\sigma_1 + \sigma_2)(\sin⁡2 \theta)}{2}$$