An AC meter of resistance $$R_m$$ and resistance $$X_m$$ is connected in series with a resistance $$R_s$$. A shunt of impedance $$(R_{sh} + jX_{sh})$$ is applied in parallel to the existing combination of meter and $$R_s$$. The current division across the two branches will be independent of frequency when

A

$$(R_{s} + R_{m})^2 + X_{m}^2 = R_{sh}^2 + X_{sh}^2$$

B

$$\frac{X_m}{R_m + R_s} = \frac{X_{sh}}{R_{sh}}$$

C

$$\frac{R_s}{\sqrt{R_m^2 + X_m^2}} = \frac{R_{sh}}{X_{sh}}$$

D

$$\frac{X_m}{R_m} = \frac{X_{sh}}{R_{sh}}$$