In the following circuit the switch S is closed at t = 0. The charge on the capacitor C$$_1$$ as a function of time will be given by $$\left(C_{eq} = \frac{C_1 C_2}{C_1 + C_2}\right)$$:

A

$$C_1 E\left[1 - \exp\left(-\frac{tR}{C_1}\right)\right]$$

B

$$C_{eq} E \exp\left[-\frac{t}{RC_{eq}}\right]$$

C

$$C_{eq} E\left[1 - \exp\left(-\frac{t}{RC_{eq}}\right)\right]$$

D

$$C_2 E\left[1 - \exp\left(-\frac{t}{RC_2}\right)\right]$$