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Question 16

Given below are two statements:
Statement I: If the Brewster's angle for the light propagating from air to glass is $$\theta_B$$, then Brewster's angle for the light propagating from glass to air is $$\frac{\pi}{2} - \theta_B$$.
Statement II: The Brewster's angle for the light propagating from glass to air is $$\tan^{-1} \mu_g$$, where $$\mu_g$$ is the refractive index of glass.
In the light of the above statements, choose the correct answer from the options given below:

Statement I: Brewster's angle air→glass: $$\tan\theta_B = \mu_g$$. Glass→air: $$\tan\theta'_B = 1/\mu_g = \cot\theta_B = \tan(\pi/2-\theta_B)$$. So $$\theta'_B = \pi/2-\theta_B$$. TRUE.

Statement II: Brewster's angle glass→air should be $$\tan^{-1}(1/\mu_g)$$, not $$\tan^{-1}(\mu_g)$$. FALSE.

Statement I is true but Statement II is false.

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