Primary coil of a transformer is connected to $$200 \text{ V AC}$$. Primary and secondary turns of the transforms are $$100$$ and $$10$$ respectively. Secondary coil of transformer is connected to two series resistances as shown in figure. The output voltage $$(V_0)$$ is :

Transformer voltage equation: $$\frac{V_s}{V_p} = \frac{N_s}{N_p}$$

Given parameters: $$V_p = 200\text{ V},\quad N_p = 100,\quad N_s = 10$$

Calculating total secondary voltage ($$V_s$$):

$$V_s = V_p \times \frac{N_s}{N_p} = 200 \times \frac{10}{100} = 22\text{ V}$$

Applying voltage divider rule across the series resistors in the secondary circuit to find $$V_0$$:

$$V_0 = V_s \times \frac{7\text{ k}\Omega}{15\text{ k}\Omega + 7\text{ k}\Omega}$$

$$V_0 = 22 \times \frac{7}{22} = 7\text{ V}$$