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Let $$\vec{a} = 2\hat{i} + 3\hat{j} + 3\hat{k}$$ and $$\vec{b} = 6\hat{i} + 3\hat{j} + 3\hat{k}$$. Then the square of the area of the triangle with adjacent sides determined by the vectors $$(2\vec{a} + 3\vec{b})$$ and $$(\vec{a} - \vec{b})$$ is :
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