The shortest distance between the lines $$\dfrac{x - 4}{1} = \dfrac{y - 3}{2} = \dfrac{z - 2}{-3}$$ and $$\dfrac{x + 2}{2} = \dfrac{y - 6}{4} = \dfrac{z - 5}{-5}$$ is :

A

$$\dfrac{5\sqrt{6}}{6}$$

B

$$2\sqrt{5}$$

C

$$3\sqrt{5}$$

D

$$4\sqrt{5}$$