As shown in the figure, after passing through the medium 1, the speed of light $$v_2$$ in medium 2 will be: (Given $$c = 3 \times 10^8$$ m s$$^{-1}$$)

A

$$1.0 \times 10^8$$ m s$$^{-1}$$

B

$$0.5 \times 10^8$$ m s$$^{-1}$$

C

$$1.5 \times 10^8$$ m s$$^{-1}$$

D

$$3.0 \times 10^8$$ m s$$^{-1}$$