Question 134

When 2388, 4309 and 8151 are divided by a certain 3-digit number, the remainder in each case is the same. The remainder is:

Solution

Given that the number 2388, 4309, 8151

then 4309 - 2388 = 1921 = $$ 17 \times 113 $$

8151- 4309 = 3842 = $$ 2 \times 17 \times 113$$

Again 8151 - 2388 = 5766 = $$ 3 \times 17 \times 113 $$

HCF = $$ 17 \times 113 $$

Thus, $$\dfrac{2388}{113} = (Reminder = 15)$$

$$\dfrac {4309}{113} = (Reminder = 15)$$

$$\dfrac {8151}{113} = (Reminder = 15)$$

Then our Ans = 15

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