At an instant, the length of the shadow of a pole is , √3 times the height of the pole. The angle of elevation of the Sun at that moment is
Let height of pole = AB = $$h$$
Length of shadow = BC = $$x$$
Angle of elevation of sun = $$\angle$$ACB = $$\theta$$ = ?
Acc to ques : $$x = \sqrt{3} h$$
In $$\triangle$$ABC
=> $$tan \theta = \frac{AB}{BC}$$
=> $$tan \theta = \frac{h}{x}$$
=> $$tan \theta = \frac{h}{\sqrt{3} h} = \frac{1}{\sqrt{3}}$$
=> $$\theta$$ = 30°
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