Question 130
In an isosceles triangle, if the unequal angle is twice the sum of the equal angles, then each equal angle is
Solution
Let the angles of isosceles triangle be $$\alpha , \alpha , \beta$$
Now, $$\beta = 2(\alpha + \alpha)$$
=> $$\beta = 4 \alpha$$
Also, sum of angles of a triangle is 180°
=> $$2 \alpha + \beta = 180^{\circ}$$
=> $$2 \alpha + 4 \alpha = 180^{\circ}$$
=> $$\alpha = \frac{180}{6} = 30^{\circ}$$
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