Question 130

In an isosceles triangle, if the unequal angle is twice the sum of the equal angles, then each equal angle is

Solution

Let the angles of isosceles triangle be $$\alpha , \alpha , \beta$$

Now, $$\beta = 2(\alpha + \alpha)$$

=> $$\beta = 4 \alpha$$

Also, sum of angles of a triangle is 180°

=> $$2 \alpha + \beta = 180^{\circ}$$

=> $$2 \alpha + 4 \alpha = 180^{\circ}$$

=> $$\alpha = \frac{180}{6} = 30^{\circ}$$

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