For the given circuit, comment on the type of transformer used:

We need to determine the type of transformer used in the given circuit based on its input and output parameters.

From the given circuit diagram, we have the following data for the primary and secondary sides:

Primary voltage, $$V_1 = 220\text{ V}$$

Secondary power delivered to the load, $$P_2 = 60\text{ W}$$

Secondary load current, $$i_L = 0.11\text{ A}$$

The power on the secondary side of an ideal transformer can be expressed as: $$P_2 = V_2 \times i_L$$, where $$V_2$$ is the secondary output voltage.

Rearranging the formula to solve for the secondary voltage yields: $$V_2 = \frac{P_2}{i_L}$$.

Substituting the given values into the expression gives: $$V_2 = \frac{60}{0.11} \approx 545.45\text{ V}$$.

Comparing the secondary voltage with the primary voltage, we find that: $$V_2 > V_1$$ since $$545.45\text{ V} > 220\text{ V}$$.

Since the output voltage on the secondary side is greater than the input voltage on the primary side, the transformer increases the voltage level.

Therefore, the correct answer is Option C: Step-up transformer.