An electron with energy $$0.1 \text{ keV}$$ moves at right angle to the earth's magnetic field of $$1 \times 10^{-4} \text{ Wb m}^{-2}$$. The frequency of revolution of the electron will be (Take mass of electron $$= 9.0 \times 10^{-31} \text{ kg}$$)

A

$$1.6 \times 10^5 \text{ Hz}$$

B

$$5.6 \times 10^5 \text{ Hz}$$

C

$$2.8 \times 10^6 \text{ Hz}$$

D

$$1.8 \times 10^6 \text{ Hz}$$