Question 119
A steel rod of original length 200mm and final length of 200.2 mm after application of an axial tensile load of 20 kN, whatwill be the strain developed in the rod?
Solution
Original length of steel rod = $$L_o=200$$ mm
Final length of steel rod = $$L_f=200.2$$ mm
Axial tensile load = $$P=20$$ kN
=> Strain developed in the rod $$\epsilon=\frac{L_f-L_o}{L_o}$$
= $$\frac{200.2-200}{200}=0.001$$
=> Ans - (C)
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