Question 119

A man loses 20 1/2% of his money and after spending 80% of the remainder, he is left with 159. How much did he have at first ?

Solution

Let the initial amount of money be Rs z

As it is mentioned that the person looses 20 1/2% means the person is left with = (z - $$\frac{41}{2\times 100}\times z$$) = Rs 0.795 z

And it is mentioned that after spending 80 % of the remainder he is left with only Rs 159

So, 0.795 z - $$\frac{80}{100}$$ x 0.795z = 0.2 x 0.795 z = 159

z = Rs 1000

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