Question 116
Consider a trapezium PQRS in which PQ || RS. Point E internally divides RS in equal parts and PQRE forms a parallelogram. The area of triangle PSE is 37 $$cm^2$$. Find the area enclosed by the shape PQRS.
Solution
Here, the height of the parallelogram and the triangle are the same, and also the base is the same. This is because the question states that the PE divided SR into half.
.png)
The area of triangle is 1/2*b*h=1/2*x*h=37 $$\Rightarrow$$ xh=74.
Area of the PQRE is b*h=x*h=74
The total area is 37+74=111 $$cm^2$$.
