Question 117

What is the equation of a straight line that has y-intercept 5 and is perpendicular to a straight line joining (2, -3) and (4, 2)?

Solution

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The line in question (slope 'a') is perpendicular to a straight line (slope 'b') joining (2, -3) and (4, 2). Hence, a$$\times\ $$b= -1

b= $$\ \frac{\ 5}{2}$$, which makes a= $$\ \frac{\ -2}{5}$$

Hence, the equation of line with slope $$\ \frac{\ -2}{5}$$ is y= $$\ \frac{\ -2}{5}$$x + 5

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