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Each of these questions has a problem and two statements, number I and II. Decide if the information given in the statement is sufficient for answering the problem. Mark the answer as
A list contains 11 consecutive integers. What is the greatest integer on the list?
I. If x is the smallest integer on the list, then $$(x + 72)^{\frac{1}{3}} = 4$$.
II. If x is the smallest integer on the list, then $$\frac{1}{64} = x^{-2}$$.
Statement I : If x is the smallest integer on the list, then $$(x + 72)^{\frac{1}{3}} = 4$$
=> $$(x+72)=4^3=64$$
=> $$x=64-72=-8$$
Now, 11 consecutive integers starting from -8 : -8,-7,-6,-5,-4,-3,-2,-1,0,1,2
Thus, greatest integer is 2 and statement I alone is sufficient.
Statement II : If x is the smallest integer on the list, then $$\frac{1}{64} = x^{-2}$$
=> $$(x)^{2}=64$$
=> $$x=\pm8$$
Since, there are two values of $$x$$, we cannot find the greatest integer. statement II alone is insufficient.
=> Ans - (A)
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