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Study the graph to answer these questions.
The graph below shows the number of graduates (in '000) of different streams, in six different states of country.

In which two states is the number of IT graduates, as a percentage of the total number of graduates in that state, most nearly the same?
Percentage of IT graduates in state A,
= $$\frac{31}{46 + 31 + 23 + 22} \times 100 = \frac{3100}{122} = 25.4$$%
Percentage of IT graduates in state B,
= $$\frac{38}{41 + 38 + 28 + 28} \times 100 = \frac{38}{135} = 28.14$$%
Percentage of IT graduates in state C,
= $$\frac{22}{62 + 34 + 26 + 23} \times 100 = \frac{22}{145} = 15.17$$%
Percentage of IT graduates in state D,
= $$\frac{18}{59 + 45 + 31 + 18} \times 100 = \frac{18}{153} = 11.76$$%
Percentage of IT graduates in state E,
= $$\frac{27}{38 + 28 + 24 + 12} \times 100 = \frac{27}{102} = 26.47$$%
Percentage of IT graduates in state F,
= $$\frac{16}{54 + 25 + 16 + 11} \times 100 = \frac{16}{106} = 15.09$$%
$$\therefore$$ Percentage of IT graduates in C and F is mostly same.
Hence, option A is the correct answer.
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