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Land Cruiser Prado, the latest SUV from Toyota Motors, consumes diesel at the rate of $$\frac{1}{400}\left\{ \frac{1000}{x} + x\right\}$$litres per Km. when travelling at the speed of x km/hr. The diesel costs Rs. 65 per litre and the driver is paid Rs. 50 per hour. Find the steady speed that will minimize the total cost of a 1000 km trip?
Total cost=Fuel cost+ Driver’s cost
Fuel cost=Total distance × Cost of Diesel per km
Fuel cost=1000×[1/400 {(1000/x)+x} ]×65
Fuel cost = 162500/x + 162.5x
Now, substituting the values from the given choices, we find that at x=36, the total cost is minimum.
Hence. Option B is correct.
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