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If $$a$$ and $$b$$ are integers with $$a + \frac{1}{b} = \frac{7}{2}$$ and $$ab + \frac{1}{ab} = \frac{37}{6}$$, then $$\frac{a^2 + b^2}{a^2 - b^2} = $$
From $$ab + \frac{1}{ab} = \frac{37}{6} = 6 + \frac{1}{6}$$ and $$ab$$ an integer we get $$ab = 6$$. The integer pairs with product 6 that also satisfy $$a + \frac{1}{b} = \frac{7}{2}$$ force $$a = 3$$ and $$b = 2$$. Hence $$\frac{a^2 + b^2}{a^2 - b^2} = \frac{9 + 4}{9 - 4} = \frac{13}{5}$$.
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