Question 109

The sum of the ages of two brothers, having a difference of 8 years between them, will double after 10 years. What is the ratio of the age of the younger brother to that of the elder brother ?

Solution

Let the age of 1st brother be A years and of 2nd be B years

It is given that A-B = 8 years............(1)

and after 10 years ,

(A +10)+(B + 10) = 2(A+B)

A + B = 20 .............(2)

from equation 1 and 2

A = 14 years

B = 6 years

$$\frac{B}{A}$$ = $$\frac{6}{14}$$ = $$\frac{3}{7}$$

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