Question 110

On decreasing each side of an equilateral triangle by 2 cm, there is a decrease of 4√3 cm 2 in its area. The length of each side of the triangle is

Area of an equilateral triangle= $$(\frac{\sqrt3}{4})\times(a)^{2}$$
where a is side.
When a reduced to (a-2)
Area difference = 4$${\sqrt3}$$
$$(\frac{\sqrt3}{4})$$($$(a)^{2}-(a-2)^{2})$$= 4$${\sqrt3}$$
4a-4=16
a=5 (C)

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