Question 109

A Box contains three different types of old coins in the ratio 3:5:7, the values of old coins are 1 rupee, 5 rupees and 10 rupees respectively. If the total value of the coins in the box is Rs.294, find the number of coins values 10 rupees.

Solution

Let number of 1 rupee, 5 rupees and 10 rupees respectively be $$3x,5x$$ and $$7x$$

Total amount = $$(1\times3x)+(5\times5x)+(10\times7x)=2352$$

=> $$3x+25x+70x=294$$

=> $$x=\frac{294}{98}=3$$

$$\therefore$$ Number of 10 rupees coins = $$7\times3=21$$

=> Ans - (D)