A student goes to school at the rate of $$\frac{5}{2}$$ km/hr and reaches 6 minutes late. If he travels at the speed of 3 km/hr he is 10 minutes early. What is the distance to the school?

Let the distance to the school = $$d$$

Time taken by him when he goes to school at a speed of $$\frac{5}{2}$$km/h = $$\frac{2d}{5}$$

Time taken by him when he goes to school at a speed of 3km/h = $$\frac{d}{3}$$

According to the problem,

$$\frac{2d}{5}-\frac{d}{3}=\frac{16}{60}$$ hours

$$=$$> $$\frac{6d-5d}{15}=\frac{16}{60}$$

$$=$$> $$\frac{d}{15}=\frac{16}{60}$$

$$=$$> $$d=4$$ km

$$\therefore\ $$The distance to the school = 4 km

Hence, the correct answer is Option B