A train, 240 in long crosses a man walking along the line in opposite direction at the rat4 of 3 kmph in 10 seconds. The speed of the train is
As man and train are coming to each other
and we assume speed of train = $$x$$
hence its relative speed will be ($$x$$ + 3)
relative distance travelled = 240m = .24 km
time taken = 10 sec. = $$\frac{10}{3600}$$ hr
so ($$x$$ + 3) = $$\frac{.24}{\frac{10}{3600}}$$
solving the eq. we will $$x$$ equals to 83.4 kmph
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