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Question 102

In a 100m race, Kamal defeats Bimal by 5 seconds. If the speed of Kamal is 18 Kmph, then the speed of Bimal is

As we know distance is constant for vimal and kamal and that is equal to 100 m.
hence $$V_{bimal}\times t_{bimal}$$ = 100
or $$V_{bimal}\times (t_{kamal} + 5)$$ = 100
where $$t_{kamal}$$ will be $$\frac{Distance}{V_{kamal}}$$ i.e. $$\frac{100 m}{18 kmph}$$
so $$V_{bimal}\times (\frac{100 m}{18 kmph} + 5)$$ = 100
After  solving above equation we will get $$V_{bimal}$$ = 4 $$\frac{m}{s}$$ or 14.4 kmph

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