Question 102

$$\frac{1}{\log_x yz + 1} + \frac{1}{\log_y xz + 1} + \frac{1}{\log_z xy + 1}$$ = ?

Solution

The equation becomes

==>$$\frac{1}{\log_x yz + log_x x} + \frac{1}{\log_y xz + log_y y} + \frac{1}{\log_z xy + log_z z}$$

$$\frac{1}{\log_x xyz} + \frac{1}{\log_y xyz} + \frac{1}{\log_z xyz}$$

$$log_{xyz} xyz$$

=1.

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