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In a convex quadrilateral PQRS, the areas of triangles PQS, QRS and PQR are in the ratio $$3 \colon 4 \colon 1$$. A line through Q cuts PR at A and RS at B such that $$PA \colon PR = RB \colon RS$$. Prove that A is the midpoint of PR and B is the midpoint of RS.
Correct Answer: 0
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