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Educational materials for IPMAT and IIMB UG preparation
10Â years, 1Â month ago
what is the remainder when 25! is divided by 29?
10Â years, 1Â month ago
29 is prime. So, 28! mod 29 = 28
25! * 26*27*28 mod 29 = 28
=> R*(-3)*(-2)*(-1) mod 29 = 28
=> -6R mod 29 = 28
or, 23 R mod 29 = 28
When R = 5, the equation becomes 115 mod 29 = 28, which is true.
So, the remainder is 5.
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