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9 years ago
what is the remainder when 25! is divided by 29?
9 years ago
29 is prime. So, 28! mod 29 = 28
25! * 26*27*28 mod 29 = 28
=> R*(-3)*(-2)*(-1) mod 29 = 28
=> -6R mod 29 = 28
or, 23 R mod 29 = 28
When R = 5, the equation becomes 115 mod 29 = 28, which is true.
So, the remainder is 5.
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