Join WhatsApp Icon JEE WhatsApp Group

P-Block Elements Formulas for JEE 2027, Download PDF Now

Dakshita Bhatia

380

Jun 16, 2026

Latest Updates:

  • June 30, 2026: Check JoSAA Round 2 Seat Allotment Result 2026 date, reporting schedule, SAF payment, Freeze, Float, Slide options, OR-CR and next counselling steps..Read More
  • June 30, 2026: Understand JoSAA Business Rules 2026, including eligibility, seat allocation, Freeze, Float, Slide, documents, fees and counselling mistakes to avoid easily.Read More
P-Block Elements Formulas for JEE 2027, Download PDF Now

P-Block Elements Formulas for JEE 2027

p-Block Elements is an important and scoring chapter in JEE Chemistry for 2027 aspirants. This chapter mainly covers elements from Groups 13 to 18 of the periodic table and helps students understand their properties, trends, reactions, and important compounds. Key elements such as boron, carbon, nitrogen, oxygen, halogens, and noble gases are discussed in detail, making this chapter highly useful for solving concept-based and reaction-based questions in JEE Main and JEE Advanced.

The chapter also includes the structure, preparation methods, chemical behaviour, and uses of important compounds, which are frequently tested in the exam. Since many questions from p-Block Elements are based on reactions, exceptions, and periodic trends, regular revision is very important. For quick preparation, students can refer to a well-organised JEE Mains Chemistry Formula PDF 2027, which helps them revise important reactions, key points, and concepts in one place. A good JEE Formula PDF 2027 can make last-minute revision easier and improve accuracy during the exam.

Group 13: Boron Family Formulas for JEE 

Overview of p-Block Groups

GroupNameValence ConfigElements
13Boron family$$ns^2\,np^1$$B, Al, Ga, In, Tl
14Carbon family$$ns^2\,np^2$$C, Si, Ge, Sn, Pb
15Pnictogens$$ns^2\,np^3$$N, P, As, Sb, Bi
16Chalcogens$$ns^2\,np^4$$O, S, Se, Te, Po
17Halogens$$ns^2\,np^5$$F, Cl, Br, I, At
18Noble gases$$ns^2\,np^6$$He, Ne, Ar, Kr, Xe, Rn

Definition: Inert Pair Effect

The reluctance of the $$s$$-electrons of the valence shell to participate in bonding in heavier p-block elements. As we go down a group, the lower oxidation state becomes more stable. Example: Tl prefers +1 over +3; Pb prefers +2 over +4.

Boron Compounds

Borax (Na$$_2$$B$$_4$$O$$_7$$ · 10H$$_2$$O)

  • Dissolves in water to give alkaline solution: $$\text{Na}_2\text{B}_4\text{O}_7 + 7\text{H}_2\text{O} \to 2\text{NaOH} + 4\text{H}_3\text{BO}_3$$
  • Borax bead test: On heating: $$\text{Na}_2\text{B}_4\text{O}_7 \xrightarrow{\Delta} 2\text{NaBO}_2 + \text{B}_2\text{O}_3$$ (transparent glass bead)

Boric Acid (H$$_3$$BO$$_3$$)

  • Weak, monobasic Lewis acid (not Bronsted acid)
  • Accepts OH$$^-$$ from water: $$\text{B(OH)}_3 + \text{H}_2\text{O} \rightleftharpoons \text{B(OH)}_4^- + \text{H}^+$$
  • On heating: H$$_3$$BO$$_3$$ → HBO$$_2$$ (metaboric acid) → B$$_2$$O$$_3$$ (boron trioxide)

Important Note

Boric acid is a Lewis acid, not a protonic (Bronsted) acid. It accepts an OH$$^-$$ from water rather than donating H$$^+$$. This distinction is commonly tested in JEE.

Diborane (B$$_2$$H$$_6$$)

  • Contains 4 terminal B–H bonds (normal 2c-2e bonds)
  • Contains 2 bridging B–H–B bonds (3-centre 2-electron bonds, "banana bonds")
  • Each boron is $$sp^3$$ hybridised; molecule is electron deficient
  • With water: $$\text{B}_2\text{H}_6 + 6\text{H}_2\text{O} \to 2\text{H}_3\text{BO}_3 + 6\text{H}_2\uparrow$$

BF$$_3$$ vs AlCl$$_3$$

  • BF$$_3$$: $$sp^2$$ hybridised, trigonal planar, strong Lewis acid. Does not dimerise (F provides $$p\pi$$–$$p\pi$$ back bonding)
  • AlCl$$_3$$: Exists as dimer Al$$_2$$Cl$$_6$$ in vapour phase (bridging chlorines). Strong Lewis acid, catalyst in Friedel-Crafts reactions. Each Al is $$sp^3$$ in the dimer.

Group 14: Carbon Family Formulas for JEE 

Definition: Catenation

The ability of an atom to form bonds with other atoms of the same element, creating long chains, branched chains, or rings. Carbon has the highest catenation tendency (C–C bond = 348 kJ/mol). Order: C ≫ Si > Ge > Sn > Pb.

Allotropes of Carbon

AllotropeHybridisationStructureProperties
Diamond$$sp^3$$3D tetrahedral networkHardest substance, insulator
Graphite$$sp^2$$Layered hexagonal sheetsSoft, lubricant, conductor
Fullerene (C$$_{60}$$)$$sp^2$$Spherical cageSoluble in organic solvents

Graphite conducts because delocalised $$p$$-electrons are mobile across layers. It is soft because layers slide over each other (weak van der Waals forces).

Carbon Monoxide (CO)

  • Colourless, odourless, highly toxic (binds to haemoglobin 200× more strongly than O$$_2$$)
  • Strong reducing agent: $$\text{Fe}_2\text{O}_3 + 3\text{CO} \to 2\text{Fe} + 3\text{CO}_2$$ (blast furnace)
  • Acts as a ligand (e.g., [Ni(CO)$$_4$$])
  • Triple bond: $$:\text{C} \equiv \text{O}:$$ (isoelectronic with N$$_2$$)

Carbon Dioxide (CO$$_2$$)

  • Linear molecule ($$sp$$ hybridised), O=C=O, bond angle 180°
  • Turns lime water milky: $$\text{Ca(OH)}_2 + \text{CO}_2 \to \text{CaCO}_3\downarrow + \text{H}_2\text{O}$$
  • Acidic oxide: $$\text{CO}_2 + \text{H}_2\text{O} \rightleftharpoons \text{H}_2\text{CO}_3$$ (weak)
  • Does not support combustion (except Mg burns in CO$$_2$$)
  • Solid CO$$_2$$ = "dry ice" (sublimes at $$-78$$°C)

Group 15: Nitrogen Family Formulas for JEE 

Ammonia (NH$$_3$$)

Haber process: $$\text{N}_2 + 3\text{H}_2 \xrightarrow[\text{200 atm, Fe}]{\text{700 K}} 2\text{NH}_3$$

  • Trigonal pyramidal ($$sp^3$$, one lone pair), bond angle ≈ 107°
  • Weak base: $$\text{NH}_3 + \text{H}_2\text{O} \rightleftharpoons \text{NH}_4^+ + \text{OH}^-$$
  • Lewis base: forms complexes like [Cu(NH$$_3$$)$$_4$$]$$^{2+}$$ (deep blue)
  • Catalytic oxidation: $$4\text{NH}_3 + 5\text{O}_2 \xrightarrow{\text{Pt/Rh}} 4\text{NO} + 6\text{H}_2\text{O}$$
  • Test: Turns moist red litmus blue; white fumes with HCl ($$\text{NH}_4\text{Cl}$$)

Nitric Acid (HNO$$_3$$) — Ostwald Process

$$4\text{NH}_3 + 5\text{O}_2 \xrightarrow{\text{Pt, 500K}} 4\text{NO} + 6\text{H}_2\text{O}$$

$$2\text{NO} + \text{O}_2 \to 2\text{NO}_2$$

$$3\text{NO}_2 + \text{H}_2\text{O} \to 2\text{HNO}_3 + \text{NO}$$

  • Strong acid, powerful oxidising agent
  • Aqua regia = 3 parts conc. HCl + 1 part conc. HNO$$_3$$ (dissolves Au and Pt)
  • With Cu (dilute): $$3\text{Cu} + 8\text{HNO}_3 \to 3\text{Cu(NO}_3)_2 + 2\text{NO}\uparrow + 4\text{H}_2\text{O}$$
  • With Cu (conc.): $$\text{Cu} + 4\text{HNO}_3 \to \text{Cu(NO}_3)_2 + 2\text{NO}_2\uparrow + 2\text{H}_2\text{O}$$

Phosphorus Compounds

Allotropes of Phosphorus

AllotropeStructureProperties
White P (P$$_4$$)TetrahedralWaxy, poisonous, glows in dark, most reactive
Red PPolymeric chainsNon-poisonous, less reactive
Black PLayered (like graphite)Least reactive, semiconductor

Phosphorus Halides

  • PCl$$_3$$: $$sp^3$$, trigonal pyramidal. Hydrolyses: $$\text{PCl}_3 + 3\text{H}_2\text{O} \to \text{H}_3\text{PO}_3 + 3\text{HCl}$$
  • PCl$$_5$$: $$sp^3d$$, trigonal bipyramidal (vapour). Axial bonds longer/weaker. In solid: [PCl$$_4$$]$$^+$$[PCl$$_6$$]$$^-$$ (ionic). Hydrolyses: $$\text{PCl}_5 + 4\text{H}_2\text{O} \to \text{H}_3\text{PO}_4 + 5\text{HCl}$$

Oxoacids of Phosphorus

OxoacidFormulaBasicityP–H Bonds
Hypophosphorous acidH$$_3$$PO$$_2$$Monobasic2
Phosphorous acidH$$_3$$PO$$_3$$Dibasic1
Phosphoric acidH$$_3$$PO$$_4$$Tribasic0

Key rule: Only H atoms bonded to O (as O–H) are acidic. H atoms bonded directly to P (as P–H) are not acidic.

Group 16: Oxygen Family Formulas for JEE 

Ozone (O$$_3$$)

  • Pale blue gas, pungent smell; diamagnetic
  • Angular shape ($$sp^2$$), bond angle ≈ 117°
  • Powerful oxidising agent: $$\text{O}_3 \to \text{O}_2 + [\text{O}]$$
  • Detected by: turns moist KI-starch paper blue
  • $$\text{O}_3 + 2\text{KI} + \text{H}_2\text{O} \to 2\text{KOH} + \text{I}_2 + \text{O}_2$$

Sulphuric Acid — Contact Process

$$\text{S} + \text{O}_2 \to \text{SO}_2$$

$$2\text{SO}_2 + \text{O}_2 \xrightarrow[\text{720 K}]{\text{V}_2\text{O}_5} 2\text{SO}_3$$

$$\text{SO}_3 + \text{H}_2\text{SO}_4 \to \text{H}_2\text{S}_2\text{O}_7$$ (oleum)

$$\text{H}_2\text{S}_2\text{O}_7 + \text{H}_2\text{O} \to 2\text{H}_2\text{SO}_4$$

  • Strong dibasic acid; powerful dehydrating agent and oxidising agent
  • Chars sugar: $$\text{C}_{12}\text{H}_{22}\text{O}_{11} \xrightarrow{\text{H}_2\text{SO}_4} 12\text{C} + 11\text{H}_2\text{O}$$
  • Hot conc. with Cu: $$\text{Cu} + 2\text{H}_2\text{SO}_4 \to \text{CuSO}_4 + \text{SO}_2\uparrow + 2\text{H}_2\text{O}$$

Oxoacids of Sulphur

OxoacidFormulaOxidation State of S
Sulphurous acidH$$_2$$SO$$_3$$+4
Sulphuric acidH$$_2$$SO$$_4$$+6
Thiosulphuric acidH$$_2$$S$$_2$$O$$_3$$+2 (average)
Peroxodisulphuric acidH$$_2$$S$$_2$$O$$_8$$+6
OleumH$$_2$$S$$_2$$O$$_7$$+6

Group 17: Halogens Formulas for JEE 

Properties of Hydrogen Halides

PropertyHFHClHBrHI
Bond strengthStrongestWeakest
Acidic strengthWeakestStrongest
Reducing powerWeakestStrongest
Thermal stabilityMost stableLeast stable

HF is a weak acid (strong H–F bond, 568 kJ/mol); all others are strong acids.

Important: HF is Unique

  • Weak acid despite F being the most electronegative element (very strong H–F bond)
  • Attacks glass: $$\text{SiO}_2 + 4\text{HF} \to \text{SiF}_4 + 2\text{H}_2\text{O}$$ (glass etching)
  • Forms hydrogen bonds → anomalously high boiling point

Interhalogen Compounds

TypeExamplesHybridisationShape
XX'ClF, BrF, ICl, IBr$$sp^3$$Linear
XX'$$_3$$ClF$$_3$$, BrF$$_3$$, ICl$$_3$$$$sp^3d$$T-shaped
XX'$$_5$$BrF$$_5$$, IF$$_5$$$$sp^3d^2$$Square pyramidal
XX'$$_7$$IF$$_7$$$$sp^3d^3$$Pentagonal bipyramidal

Oxoacids of Chlorine

OxoacidFormulaOxidation StateAcidic Strength
Hypochlorous acidHOCl+1Weakest
Chlorous acidHClO$$_2$$+3
Chloric acidHClO$$_3$$+5
Perchloric acidHClO$$_4$$+7Strongest

Trend: More oxygen atoms → stronger acid (negative charge delocalised over more O atoms).

Group 18: Noble Gases Formulas for JEE 

Compounds of Xenon with Fluorine

CompoundHybridisationShapeLone Pairs
XeF$$_2$$$$sp^3d$$Linear3
XeF$$_4$$$$sp^3d^2$$Square planar2
XeF$$_6$$$$sp^3d^3$$Distorted octahedral1
XeO$$_3$$$$sp^3$$Pyramidal1

Hydrolysis:

  • $$\text{XeF}_2 + \text{H}_2\text{O} \to \text{Xe} + 2\text{HF} + \frac{1}{2}\text{O}_2$$
  • $$\text{XeF}_6 + 3\text{H}_2\text{O} \to \text{XeO}_3 + 6\text{HF}$$

Important Note

Among noble gases, only Kr and Xe form compounds. He, Ne, and Ar do not form stable compounds. Kr forms only KrF$$_2$$ (unstable). Xenon forms the widest range of compounds because its outer electrons (5th shell) are loosely held.

Key Trends Across p-Block Quick Reference for JEE 

Important Trends Across p-Block Groups

Inert pair effect: Stability of lower oxidation state increases down each group (Tl$$^+$$ > Tl$$^{3+}$$; Pb$$^{2+}$$ > Pb$$^{4+}$$)

Catenation: C ≫ Si > Ge > Sn > Pb

Maximum covalency: Period 2 elements limited to 4; Period 3 onwards can expand octet

Acidic strength of hydrides: Increases across a period (CH$$_4$$ < NH$$_3$$ < H$$_2$$O < HF) and down a group (HF < HCl < HBr < HI)

Thermal stability of hydrides: Decreases down each group

Oxidising power: F$$_2$$ > Cl$$_2$$ > Br$$_2$$ > I$$_2$$

Tip: For JEE, memorise: (1) structures of XeF$$_2$$, XeF$$_4$$, XeF$$_6$$, XeO$$_3$$, (2) interhalogen shapes (T-shaped, square pyramidal, pentagonal bipyramidal), (3) oxoacids of P, S, and Cl with basicity/strength trends, (4) allotropes of C and P, and (5) properties of HF that make it anomalous.

P-Block Elements Formulas for JEE 2027: Conclusion

P-Block Elements Formulas for JEE 2027 are very useful for students who want to revise Chemistry in a structured and exam-focused way. This chapter covers important elements from Groups 13 to 18 and includes several high-value topics such as group trends, important compounds, reactions, oxoacids, interhalogen compounds, noble gas compounds, and special properties like inert pair effect and catenation. Since many questions in JEE Main and JEE Advanced are based on direct concepts, exceptions, and reaction trends, students should revise this chapter regularly.

A well-prepared P-Block Elements Formula PDF for JEE 2027 can help aspirants save time during revision and improve their accuracy in Chemistry. Instead of reading the entire chapter repeatedly, students can use a concise formula PDF to revise important reactions, structures, compounds, and trends before mock tests and final exams. With consistent revision and question practice, p-Block Elements can become a scoring topic in JEE Chemistry.

How helpful did you find this article?

Related Blogs

Frequently Asked Questions

Predict Colleges for Your JEE Rank

(Based on JoSAA 2026 Cutoff Data)

Add Cracku as preferred source on Google

Recent Blogs