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Question
On selling a table for Rs. 210 and Rs. 420 there will be loss of L1% and L2% respectively.
On selling a table for Rs. 210 and Rs. 420 there will be loss of L1% and L2% respectively.
If L1–L2 = 7, then what is the cost price of table
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Answer
CP =x
Since its loss so,
L1= (x-210/x ) *100
L2= (x-420/x) *100
L1-L2 = 100*210/x =7
x=3000
Answer
CP of table = Rs. 3000
Let the CP of the Table be 100.
With some trial and error you can find that if you sell the table for Rs. 7 and Rs. 14 (notice that one price is twice the other, as given in the question), you will incur losses of 93%(L1) and 86%(L2) respectively. Here L1 - L2 = 7, which satisfies the given condition.
Now you can use the unitary method -
Rs. 7 corresponds to Rs. 210
Rs. 1 correspond to Rs. 30
Rs. 100 correspond to Rs. 3000 (which is the CP of the Table)
