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Mr. Lal sells only chemical Y .During the day he seels (1/11)th of the totatl quantity of the chemical with him in the morning. He observes that the total quantity of the chemical with him in the morning is 10% less than the quantity of chemical with him on the previous night. This is because the chemical Y evaporates during the course of night. Everyday he increases the selling price of the chemical by 10% with respect to the selling price of the chemical on the previous day. The cost price of the chemical is Rs 8/litre whereas on the first day he sells the chemical at Rs 10/litre
Mr. Lal sells only chemical Y .During the day he seels (1/11)th of the totatl quantity of the chemical with him in the morning. He observes that the total quantity of the chemical with him in the morning is 10% less than the quantity of chemical with him on the previous night. This is because the chemical Y evaporates during the course of night. Everyday he increases the selling price of the chemical by 10% with respect to the selling price of the chemical on the previous day. The cost price of the chemical is Rs 8/litre whereas on the first day he sells the chemical at Rs 10/litre
Q) If the total quantity of the chemical with him on the morning of the first day is 11000 litres, then what is the total profit made by him after he has completely sold all the chemical with him ?
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Answer
Hi
The total quantity on the morning of the first is 1100. So he will sell 1100/11 = 100 litres on first day. The price is 8 per litre so earnings would be 800
Second day he will sell 900/11 litres of chemical and earnings would be 900/11*8.8 = 900*.8 = 720
Similarly on third day the the chemical sold will be 8100/121. Hence the earnings would be 8100/121*8.8*1.1 = 648. Thus we can see that it forms a GP with a common ratio of 9/10. Thus the required sum would be
800/(1-9/10) = Rs 8000
Hope that helps.
