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3Â years, 1Â month ago
3Â years, 1Â month ago
Hi
Let initial volume be V liters
Now petrol :99 and kerosene : V-99
Now when volume is 198 less than mixture
so we get V-198 as mixture volume
So by given condition :
Petrol volume : 99 and kerosene :V-297
Now by condition
(99/V-198) *100 -40/3 =(99/V)(100)
So we get
V(V-198)=495*297
So V =495
Therefore petrol concentration = (99/495)*100 =20
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