If the lengths of diagonals DF, AG and CE of the cube shown in the adjoining figure are equal to the three sides of a triangle, then the radius of the circle circumscribing that triangle will be? https://cracku.in/media/uploads/2015/07/08/geom12.PNG

here is my doubt
so if a side of equilateral …

Question

If the lengths of diagonals DF, AG and CE of the cube shown in the adjoining figure are equal to the three sides of a triangle, then the radius of the circle circumscribing that triangle will be? https://cracku.in/media/uploads/2015/07/08/geom12.PNG

here is my doubt
so if a side of equilateral traingle is √ 3* x.
its circumradius should be equal to the side of a equilateral traingle?

Shubham Nagoria · Answer

Thanks got it

Jay · Answer

Dear Shubham, Circumradius=a*b*c/4A for a triangle, where a,b,c are sides and A is its area. Hence the answer to the above question is "x". The side of the triangle as you found out is √ 3* x. Hope this helps. :)

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