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3 years, 12 months ago
3 years, 12 months ago
The answer should be 4. You can try all possibilities, will end up only getting (4,20,20),(8,16,20),(12,12,20) and (12, 16, 16)
3 years, 12 months ago
each side is of the for 4k,
So any side we just need to find all possible values of K
We can also do this by dividing the perimeter by 4 and the sides will be the values of k
So now we have perimeter as 11.
use the formula for the number of triangles that can be formed by given perimeter and get the result
Then answer i am getting with the above appraoch is 2 Let me know if it is right answer
11 months, 4 weeks ago
Let 4a, 4b, 4c be the sides of triangle. Then, 4(a+b+c)=44 => a+b+c=11.
We know that a+b>c & a+b+c=11 => c<5.5
(1)c=5 => a+b=6. Thus pairs satisfying this are (1,5), (2,4), (3,3).
(2)c=4 => a+b=4. Pairs are (2,5), (3,4).
(3)c=3 => a+b=8. Pairs are (4,4), (3,5).
(4)c=2 => a+b=9. Pair possible is (4,5).
(5)c=1 => a+b=10. Pair possible is (5,5).
Thus, according to my logic, the answer is 9. I may be wrong as well.
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