From the Videos Cyclicity of factors e.g. given as 2^2^2015. Can nyou explain how 2^2015 is written as 2*4^1007?

Question

Wasif Jamal · Answer

4^1007 = (2^2)^1007 = 2^(2*1007) = 2^2014 and when you multiply it with 2 it becomes 2^2015. Hence 2^2015 can be written as 2*4^1007

Bansari Zaveri · Answer

Then how is 2^4? Will it not be 2^2 and the last digit be 4?

Bansari Zaveri · Answer

Then how is 2^4? Will it not be 2^2 and the last digit be 4?

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