From the Videos Cyclicity of factors e.g. given as 2^2^2015. Can nyou explain how 2^2015 is written as 2*4^1007?

Question

Answer 1

4^1007 = (2^2)^1007 = 2^(2*1007) = 2^2014 and when you multiply it with 2 it becomes 2^2015. Hence 2^2015 can be written as 2*4^1007

Answer 2

4^1007 = (2^2)^1007 = 2^(2*1007) = 2^2014 and when you multiply it with 2 it becomes 2^2015. Hence 2^2015 can be written as 2*4^1007

Answer 3

Then how is 2^4? Will it not be 2^2 and the last digit be 4?

Answer 4

Then how is 2^4? Will it not be 2^2 and the last digit be 4?

Answer 5

Then how is 2^4? Will it not be 2^2 and the last digit be 4?

Answer 6

Then how is 2^4? Will it not be 2^2 and the last digit be 4?