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7 years, 7 months ago
From the Videos Cyclicity of factors e.g. given as 2^2^2015. Can nyou explain how 2^2015 is written as 2*4^1007?
7 years, 7 months ago
4^1007 = (2^2)^1007 = 2^(2*1007) = 2^2014 and when you multiply it with 2 it becomes 2^2015. Hence 2^2015 can be written as 2*4^1007
7 years, 6 months ago
Then how is 2^4? Will it not be 2^2 and the last digit be 4?
7 years, 6 months ago
Then how is 2^4? Will it not be 2^2 and the last digit be 4?